Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Spin-1 particles: Intrinsic Inertial Platforms.

  1. Jun 14, 2004 #1
    The simplest Stern-Gerlach spin-1 transition is the +S -> +T -> +S transition. The expression defines two events:

    1) Polarization event of the +S state when passing to the +T state, +S -> +T, from the field free region to the field/gradient volume of the Stern-Gerlach T segment. Here we arbitrarily select the +T state as the polarized state.

    2) Depolarization event of the +T state to the +S state as, +T - > +S state, when passing from the field/gradient volume of the SG segment to the +S state in the field free region (also force free region).


    "+S" means 'up' motion in an S SG segment where the field/gradient is oriented 'up' wrt the lab frame (S means 'parallel to the Z-axis', + means 'up' along S.) A T segment is rotated pi/24 (the field gradient direction) radians around the direction of motion of the spin-1 particle and is obstruction free. The S segment producing the +S state has the center and lower transition channels blocked resulting in a loss of 2/3 of the input spin-1 particle stream into the S segment.

    In general, all spin-1 particles entering the T segment and polarized to any allowed T state, pass through the T segment (we chose the +T as the polarized state), exiting in the prepolarized spin-1 +S state.

    The +S -> +T event orients the S+ spin vector to the +T state direction, say pi/24 radians, when the particle enters the field/gradient region of the T segment from the field free region. The +T -> +S event reorients the +T state to the +S state. As compass needles find north with the force of the earth's magnetic field, the +S state is recovered when transitioning from the field gradient region in the T segment to the field free region. The process as described is experimentally 100% reproducible and is equivalent to the description of an inertial frame..

    Therefore, the +T state must be +T = +T(00[+S]) where 00[+S] are those unobserved elements of the +S state that guarantees the reformation of the +S state. As this reformation is necessarily the physical reorientation of the spin vector a force is necessarily present. As there is no observed source of the reforming force, this force is definitionally nonlocal.

    The physical reorientation of the spin vector process is, therefore, intrinsic to the Spin-1 particle state transition process - better than mechanical or laser driven gyroscopes? Prolly.

    What does QM Theory predict in the more general S ->T -> S transition?. Feynman ("Lectures on Physics" Vol III CH 5) tells us that the result is as if the T segment "were not present". This is verified by experimental results. Yet, Feynman tells us naught about the +S state reforming process. He enters the quantum mechanically defined foofoo land of 'interference amplitude'.

    Block the lower and middle T segment channels and one always observes a +T particle exiting the T segment with a loss of the 2/3 of the +S state input particles to the T segment (see description above re "+S" state production).

    As used here, "observed" means physically observed directly, or inferentially, as opposed to "observed" mathematically.
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you help with the solution or looking for help too?
Draft saved Draft deleted



Similar Discussions: Spin-1 particles: Intrinsic Inertial Platforms.
  1. Spin of a particle (Replies: 17)

  2. Spin 1/2 particles (Replies: 4)

Loading...