- #1
mikefitz
- 155
- 0
An LP turntable must spin at 3.51 rad/s to play a record. How much torque must the motor deliver if the turntable is to reach its final angular speed in 1.8 revolutions, starting from rest? The turntable is a uniform disk of diameter 31 cm and mass 0.26 kg.
I know that 1.8rev is equal to 648 degrees. This means that the disc must spin 648 degrees to reach the required 3.51 rad/s for the record.
But I don't know how to begin to calculate the torque required to achieve that angular velocity. Where do I begin> Thanks
I know that 1.8rev is equal to 648 degrees. This means that the disc must spin 648 degrees to reach the required 3.51 rad/s for the record.
But I don't know how to begin to calculate the torque required to achieve that angular velocity. Where do I begin> Thanks