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Spin of 1p1n nuclei

  1. Sep 4, 2014 #1
    I am interested in the topic of the thread
    https://www.physicsforums.com/showthread.php?t=768539
    ,especially for those unpair 1p1n case.

    As I know, for the simplest case deuteron, the Jπ (groundstate here and later) is 1+ but 0+.
    This is very different to the atomic physics case. For He atom, 2 electron create the 1S0 groundstate.
    For 18F, it is again 1+, although n and p are in the same orbital d5/2, which can combine the possible 0+,1+,2+,3+,4+,5+.
    For 50V is 6+.

    Could someone help to explain? Is there theory for the 1p1n structure?
     
  2. jcsd
  3. Sep 4, 2014 #2

    Vanadium 50

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    Yes. The nuclear force is spin-dependent, so for the deuteron, the spin-1 state is lower than the spin-0 (which isn't even bound).
     
  4. Sep 4, 2014 #3
    Thanks, for 18F, is the same reason?
     
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