# Spin Statistics Theorem

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• filip97

Gold Member
i read that question and Weinberg book (A,B)-Representation of Lorentz Group: Coefficient functions of fields

why u(a,b)=Cab/sqrt(2m) ?

where Cab is Clebsch-Gordan coefficients, and m is mass of particle
Basically because transformations on ##u_{ab}(0,\sigma)## for a massive particle are transformations that don't alter momentum by boosting to another frame, i.e. occur in one frame and don't involve translation. The only transformations then are rotations, thus they are Clebsch-Gordan coefficients.

filip97
Basically because transformations on ##u_{ab}(0,\sigma)## for a massive particle are transformations that don't alter momentum by boosting to another frame, i.e. occur in one frame and don't involve translation. The only transformations then are rotations, thus they are Clebsch-Gordan coefficients.