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Spinning drum ride

  1. Apr 24, 2010 #1
    1. The problem statement, all variables and given/known data
    If a spinning drum ride cannot exceed a 10 m radius, and the riders are not to
    experience an acceleration greater than 2g, what is the maximum speed at
    which the drum can spin?


    2. Relevant equations
    No Idea


    3. The attempt at a solution
    I tried using (theta) = tan-1 of (rg/v2)
    v2 = (tan(theta))/(rg)
    v = (root) of (tan(theta))/(rg)
     
  2. jcsd
  3. Apr 24, 2010 #2

    tiny-tim

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    Hi Alcape! :smile:

    (have a theta: θ :wink:)
    What's θ? :confused: You can assume that the drum's wall are vertical. :wink:

    Now use the standard formula for centripetal acceleration :smile:
     
  4. Apr 24, 2010 #3
    If the walls are vertical then it doesn't work as it's at 90 degrees and tangent of 90 degrees then it comes out to be a mathematical error
     
  5. Apr 24, 2010 #4

    tiny-tim

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    ah … you obviously haven't seen one of these at a fairground. :biggrin:

    Yes, if the walls are smooth, it can't be done, but you can assume the walls are rough, so that friction will keep you up (or even that there's a ledge to stand on :wink:).
     
  6. Apr 24, 2010 #5
    I now have the answer if you use the formula for acceleration:a=v2/r
    and transpose it so that it becomes: v2 = a*r and therefore becomes:
    v = √(a*r) and it comes out to be 4.47...
     
  7. Apr 25, 2010 #6

    tiny-tim

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    Hi Alcape! :smile:

    (just got up :zzz: …)
    what about g ? :redface:

    (and are you sure the question isn't asking for the angular speed?)
     
  8. Apr 25, 2010 #7
    Yes I'm sure as this is question a and b asks for the angle
     
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