Imagine a drum that is 1m in diameter and .5m long made of 10mm thick steel (369Kg). The drum is stabalized by an adequate gyroscope (50Kg) attached to the outside. Oriantate the drum so that it appears as a circle in front of you. The cylinder portion of this drum is modified so that 980cm squared section (10x98) of it can be made to fall off at 9 O'clock. The 10cm dimension of the rectangle is on the radius of the cylinder. Now imagine that inside the drum is 150Kg of water spinning at 3600rpm clockwise. This all take place in zero g. Once the rectangular section falls of the drum, what motion will the drum follow? Will it go to the right, down, or some other direction? What's the final velocity of the drum? My quess is that the drum will move to the right. As for the velocity; I am thinking of calculating the total rotational kinetic energy and then using this value to calculate the linear velocity using the start mass of the drum. Equations; rotational KE=.5 * moment of inertia * angular velocity squared linear KE = .5 * mass * velocity squared mass steel = 7929.2 Kg/m^3 This is not a homework question. It came from me, washing machine, spin cycle.