- #1
maximus123
- 50
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Hello everyone, here is my problem
two electrodes. Which seems like it must be relevant due to the similarity with the intended final result
Any help on how to go about this problem would be greatly appreciated
I'm not sure where to start with this problem, I suppose if the phase difference due to the circulating current is negligible then the total phase difference can be writtenConsider the SQUID shown in the figure (figure is attached to this post if it helps). The loop is made of a
superconducting metal and the superconducting phase must be single-valued
at every point. This means that the total phase difference around the loop
must be an integer multiple of 2[itex]\pi[/itex]. i.e
[itex]\Delta\phi_{tot}=2n\pi\\[/itex][itex]\Delta\phi_{a}[/itex] and [itex]\Delta\phi_{b}[/itex] are the phase differences across the junctions a and b, while [itex]\Delta\phi_{I}[/itex] and [itex]\Delta\phi_{B}[/itex] are the phase differences due to the circulating current I and applied magnetic field B respectively. However in circuit QED, the SQUIDs usually have a
and
[itex]\\\Delta\phi_{tot}=\Delta\phi_{a}+\Delta\phi_{b}+\Delta\phi_{I}+ \Delta \phi_{B}\\[/itex]
small intrinsic inductance. Thus the phase difference [itex]\Delta\phi_{I}[/itex] is negligible.
Explain why [itex]\Delta\phi_{B}[/itex] can be written as
[itex]\Delta\phi_{B}=2\pi\frac{\Phi}{\Phi_{0}}[/itex]Where [itex]\Phi[/itex] is the flux due to the applied magnetic field and [itex]\Phi_{0} [/itex] is the flux quantum where
[itex]\Phi_{0}=\frac{h}{2e}[/itex]
[itex]\Delta\phi_{tot}=\Delta\phi_{a}+\Delta\phi_{b}+ \Delta \phi_{B}[/itex]
In our notes we also have it that [itex]V=\frac{\Phi_{0}}{2\pi}\dot{\delta}[/itex]
Where [itex]\delta[/itex] is the difference between the superconducting phase in the two electrodes. Which seems like it must be relevant due to the similarity with the intended final result
Any help on how to go about this problem would be greatly appreciated