1. The problem statement, all variables and given/known data A spool of thread consists of a cylinder of radius R1 = 6.6 cm with end caps of radius R2 = 9.3 cm as depicted in the end view shown in the figure below. The mass of the spool, including the thread, is m = 290 g. The spool is placed on a rough, horizontal surface so that it rolls without slipping when a force = 0.690 N acting to the right is applied to the free end of the thread. For the moment of inertia treat the spool as being a solid cylinder of radius R1, as the extended edges are thin and therefore light. (a) What is the acceleration of the spool? Take positive to be to the right. http://www.webassign.net/serpse8/10-p-085.gif 2. Relevant equations Solid Cylinder I = 1/2(M)(r)^2 3. The attempt at a solution I need some help with this problem. I don't think my attempt is even correct. But my thought is since T = I*A. Then I just need to solve for A. A = T*I. The moment of inertia is what is stumping me. I'm not sure if I'm doing this correctly. I = 1/2(.3)(.066) = 0.0099. This does not solve the problem adequately. Thanks of the help! *Where T is force A is angular acceleration I is moment of inertia.