1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Spring and centrifugal force

  1. Jun 6, 2012 #1

    i found the following equation that a spring(with constant k) , a mass m rotating with angular velocity ω, will have a constant angle [itex]\alpha[/itex] to the vertical axis that is given by
    [itex]cos(\alpha)=\frac{g}{\omega^2 l}(1-\frac{m \omega^2}{k})[/itex]
    this looks similar to something like [itex]cos(\alpha)=F_{gravitation}/F_{centripetal}-F_{gravitation}/F_{spring}[/itex] but i do not see the geometrical idea behind this.

    i am not sure whether this equation is correct at all, I found it in my physics schoolbook

    Attached Files:

  2. jcsd
  3. Jun 6, 2012 #2
    The equation seems to be OK.
    In order to find it you could apply Newton's second law for the vertical and horizontal directions. Use the equation for elastic force and centripetal acceleration, too.
  4. Jun 6, 2012 #3
    thank you for this hint. now, i found it by myself.
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook