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Spring and Mass Question

  1. Nov 2, 2014 #1
    1. The problem statement, all variables and given/known data
    A 22 kg block oscillates back and forth along a straight line on a frictionless horizontal surface. Find the oscillation frequency, if its displacement from the origin is given by

    x(t) = (22.0 cm)·cos((25.0 rad/s)t + π).

    2. Relevant equations
    angular frequency=sqrt(k/m)
    period=2pisqrt(m/k)
    period=1/frequency

    3. The attempt at a solution
    okay so from the equation they gave us i think the 22.0 cm (0.22m) is the amplitude of the oscillation, and 25.0 rad/s is the angular frequency, and the pi is the is the phase angle. So im trying to solve for oscillation frequency but im not sure how to start the problem. Any solid help with trying to start this problem would be appreciated, Thanks!
     
  2. jcsd
  3. Nov 2, 2014 #2

    Doc Al

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    Staff: Mentor

    How is angular frequency related to frequency of the oscillation?
     
  4. Nov 2, 2014 #3
    Im honestly not sure how they are related, i feel like that is part of the reason why im lost when it comes to this question. Any help on trying to understand there relationship?
     
  5. Nov 3, 2014 #4

    Doc Al

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    Staff: Mentor

    Angular frequency tells you how many radians per second. How many radians are there in one complete oscillation?
     
  6. Nov 3, 2014 #5
    There is 2pi radians in one oscillation isn't there?
     
  7. Nov 3, 2014 #6

    Doc Al

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    Staff: Mentor

    Exactly. So to convert ordinary frequency (##f##) in cycles/sec to angular frequency (##\omega##) in radians/sec, what would you have to do?
     
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