Spring compressed by two boxes

  • Thread starter madah12
  • Start date
  • #1
madah12
326
1

Homework Statement


there is a problem in my final that I can't actually remember the values of the variables but I got 1 out of 4 grade in it and I was wondering what's wrong with my solution

I am just going to write the variables because I don't know the numbers:

a spring compressed equal distances by two boxes of the same mass the spring is not attached to the boxes when it is released one of the boxes moves with a velocity v calculate the total compression distance of the spring

Homework Equations





The Attempt at a Solution


by the conservation of momentum v1=-v2 and they have the same magnitude
E1=E2
.5k xT^2= .5m(v1)^2 + .5m(v2)^2= mv^2
xT=((2mv^2)/k)^.5

(v_1 ,m and k are given and the spring's mass is negligible )
 

Answers and Replies

  • #3
cupid.callin
1,137
0
Well your answer looks good

you must have done some mistake in calculation
 
  • #4
madah12
326
1
yes I thought so too I did it so fast I didn't revise the calculations
 

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