A 2.5 kg block slides along a frictionless tabletop at 6.0 m/s toward a second block (at rest) of mass 4.5 kg. A coil spring, which obeys Hooke's law and has spring constant k = 860 N/m, is attached to the second block in such a way that it will be compressed when struck by the moving block
The Attempt at a Solution
i first used M1V1 = M2V2, M2 is the block at rest, i calculated the speed of block at rest and i got 3.33 m/s, and then i use the energy equations to find the spring compression
.5 m1(6)^2 = .5k(x^2) + .5m2(3.33)^2, i solve for x, but it comes out wrong, anything im missing here?