The spring of a spring gun has a constant of 6.0. It is compressed 0.0508 meters and a ball weighing 0.009 kg is placed in the barrel against the spring. a. What is the maximum speed of the ball as it leaves the gun? Vf = sqrt (k/m)x Xi = 1.31 m/s b. If it is shot off (horizontally) a 6 ft high table, how far from the base of the table will it land? Would I use x = vot + 1/2at2 ??? To find the time and then insert into the problem? I'm confused. And the second problem.... I dead lift to a height of 30 inches 500lbs and proceed to walk the length of a football field (100 yds) and set the weight back down. Because I'm in great shape, I barely work up a sweat but how much work did I do? with 30 inches = .762m m= 500lbs, 2,224 N x= 100 yds, 91 m W = F change in X =2,224Nx(91m) = 202,384J This seems like an unreasonably high amount of work. I didn't take into consideration lifting the weight because it is perpendicular to the amount of work being done. Only the parallel force matters, right? Thanks for any and all help.