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Spring constant k please help

  1. Jul 30, 2008 #1
    how would i go about finding k with given values for mass and time?

    i have seen these equations over and over...but i feel like im missing something very important that i need..please help me

    T=2π√(m/k))

    F=-kx
     
  2. jcsd
  3. Jul 30, 2008 #2

    rock.freak667

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    [tex]T= 2 \pi \sqrt{\frac{m}{k}}[/tex]

    [tex]\Rightarrow T^2=\frac{4 \pi^2 m}{k}[/tex]

    Can you rearrange for k now?
     
    Last edited: Jul 30, 2008
  4. Jul 30, 2008 #3
    o im sorry i meant how would I go about finding T(period) with given values for time and mass...............i forgot to proof read :redface:

    those are the formulas i keep seeing everywhere

    for example if i had .10kg and 8.86 seconds for the time to find the period would i do this:

    T2=(4π2m)/((4π2m)/(8.86))

    and then at the end take the square root

    ???
     
  5. Jul 30, 2008 #4

    rock.freak667

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    How exactly was the time measured?
     
  6. Jul 30, 2008 #5
    in seconds

    8.86 seconds would be the average time for 10 vibrations in a simple harmonic motion
     
  7. Jul 30, 2008 #6

    rock.freak667

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    Period(T) is the time taken for one oscillation/vibration.


    10 oscillations/vibrations take 8.86 seconds. How much time would 1 oscillation take?
     
  8. Jul 30, 2008 #7
    OH!!! so just divide 8.86s by 10 rite??
     
  9. Jul 30, 2008 #8

    rock.freak667

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    That should yield the time period, yes.
     
  10. Jul 30, 2008 #9
    i dont believe i didnt realize that! thanku so much! ....im thinking too much lol
     
  11. Jul 30, 2008 #10

    rock.freak667

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    You just need to think about what it is you want to find.
     
  12. Jul 30, 2008 #11
    thanx again! =D
     
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