An archer pulls her bowstring back .400 m by exerting a force that increases uniformly from zero to 230 N. (a) what is the equivalent spring constant of the bow?(adsbygoogle = window.adsbygoogle || []).push({});

(b) How much work does the archer do in puling the bow?

The spring potential energy is defined by PE = 1/2kx^2. So, what does the k stand for? Force? That doesn't work. x must be the displacement of the string, which is .40, so 1/2k times (.40)^2? Friction isn't an issue, so its non conservative force. I know the theorem, but am having difficulty using it.

I know work is defined by Force times the displacement(x) and that equals Force cos theta times displacement(x). But I haven't been able to figure out theta.

Thank you, ahead of time, for your help!

Trista

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# Spring Constant Question

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