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Spring Constant

  1. Feb 18, 2008 #1
    3. A certain Spring will stretch 5.0 cm when a force of 12 N is applied to it.
    a. Calculate its spring constant in its elastic region.
    I got K=F/X so 12/.5 which comes out to be 2.4

    b. If a force of 25 N were applied to the same spring, how much would it stretch?
    I got x = f/K so 25/2.4 which comes out to be 10.42 cm.

    Is this correct?

  2. jcsd
  3. Feb 18, 2008 #2


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    Yes it looks ok. In the first part however you have 12/.5 and quoted the correct answer in N/cm. I'm guessing it was a typo.
  4. Feb 18, 2008 #3
    Actually it would have been in N/dm (decimetre), since Ashford divided the distance stretched by 10 instead of 100.

    Edit: Ah yes, I see what you mean. So ... hah, ignore this.
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