A 150g ball is thrown vertically upward from a window 10m above the ground at a speed of 30m/s. At the top of its trajectory, it compresses a spring a distance, y. (spring constant k = 1.5 N/m). If the spring is 45m above the initial starting position of the ball...
A) how high does the ball go above the ground?
B) what is the speed of the ball when it strikes the ground?
what i am thinking??? use -2g(y-yo) = vf^2-vi^2 then w=kf-ki then w= -1/2 kx^2
The Attempt at a Solution
those equations i used for part one...i am not sure where to go with part b