I have two springs arranged in series (remember circuit diagrams from physics class!).

One has a low stiffness constant (K1 = 5) and the other connected to it has a much higher contant (K2 = 100). According to the equation (as used in wikipedia):

[tex]

\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}

[/tex]

http://en.wikipedia.org/wiki/Hooke%27s_law" [Broken]

Question 1)

Using this i get my equivalent spring constant to be K = 4.76, which is less than K1?

I don't understand why. I would expect the equivalent constant to be much higher (but less than K2=100).

Question2)

This formula doesn't consider the initial lengths of each spring. How could it do so?

One has a low stiffness constant (K1 = 5) and the other connected to it has a much higher contant (K2 = 100). According to the equation (as used in wikipedia):

[tex]

\frac{1}{k}=\frac{1}{k_1}+\frac{1}{k_2}

[/tex]

http://en.wikipedia.org/wiki/Hooke%27s_law" [Broken]

Question 1)

Using this i get my equivalent spring constant to be K = 4.76, which is less than K1?

I don't understand why. I would expect the equivalent constant to be much higher (but less than K2=100).

Question2)

This formula doesn't consider the initial lengths of each spring. How could it do so?

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