- #1
Ry122
- 565
- 2
A block of mass 9.0 kg slides from rest down a frictionless incline and is stopped by a strong spring with spring constant 3.50 x 10^4 The block slides 5.00 m from the point of release to the point where it comes to rest against the spring. When the block comes to rest, how far has the spring been compressed?
My attempt:
9(9.8)sin29=42.76N
Since during the 5m of motion, energy loss is going to be equal to energy gain,
i should be able to apply this equation
1/2kx^2=fxs
x= length of movement that the spring isn't compressed during.
1/2(3.5x10^4)(5-x)^2=42.76x
this doesn't yield the correct answer as x=5.11
what am i doing wrong?
My attempt:
9(9.8)sin29=42.76N
Since during the 5m of motion, energy loss is going to be equal to energy gain,
i should be able to apply this equation
1/2kx^2=fxs
x= length of movement that the spring isn't compressed during.
1/2(3.5x10^4)(5-x)^2=42.76x
this doesn't yield the correct answer as x=5.11
what am i doing wrong?