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Spring Equilibrium Problem!

  1. Feb 2, 2010 #1
    Question is:

    A particle hangs from a spring and oscillates
    with a period of 0.4 s.
    If the mass-spring system remained at rest,
    by how much would the mass stretch it from
    its normal equilibrium position? The acceler-
    ation of gravity is 9.8 m/s2.

    And the choices are:

    1. 0.158872 m
    2. 0.0794358 m
    3. 0.124777 m
    4. 0.317743 m
    5. 0.0397179 m
    6. 0.635486 m

    I tried answer #6 but it wasn't right. I used W=SqRt of K/M
     
  2. jcsd
  3. Feb 2, 2010 #2

    rl.bhat

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    Homework Helper

    I used W=SqRt of K/M
    In the above equation put the expression for k and solve for x.
    You know that
    F = Mg = - kx
     
  4. Feb 2, 2010 #3
    how would i solve for k?
     
  5. Feb 2, 2010 #4

    rl.bhat

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    Homework Helper

    ω= sqrt(k/m) = sqrt(-mg/xm) = sqrt(-g/x)
    Square the both sides and solve for x.
     
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