I have designed a spring launcher for my class and it works really well using the range equation...x=sqrt(Rmg/KSin2(Theta)). So I have made a contraption that displaces the spring by x metres. I even have re-arranged and have it working using angles of launch and determining the range (R). Both work great.(adsbygoogle = window.adsbygoogle || []).push({});

Here is my dilemma, I am having issues figuring out the proper angle (or displacement) to use when the spring does not land on the same level as the launch...i.e. either higher or lower in a target basket. I am having a hard time figuring out how to manipulate the equations to include the height. I have tried manipulating the equation from http://www.mwit.ac.th/~Physicslab/hbase/traj.html#tra8" [Broken] but to no avail.

• x = how far you pull the spring back in meters

• R = range: how far you want the spring to go in meters

• m = mass of the spring in Kg

• g = acceleration of gravity 9.8 m/s/s

• K = spring constant in Newtons / meter

• Theta = angle of launcher from horizontal

If anyone can help me with this, it would be greatly appreciated.

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# Spring Launcher

Can you offer guidance or do you also need help?

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