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Using a smooth bore classic musket (approximately 1m length of barrel, musket ball (.0173m diameter)), what would the potential muzzle velocity of the musket ball be if the powder charge were replaced with a compressed spring?

PE=1/2kx^2

KE=1/2mv^2

Using a spring with k=128 Nm (used a calculator on engineer's edge where modulus of ridgity G was 25x10^6, wire diameter d was .2 inches, mean coil diameter D was .48 inches and number of active coils n was 40). Not sure if this is kosher or not.

Assuming friction and gravity are negligible - the musketeer keeps the weapon well lubed and is on the moon, if he pulls the trigger which releases the "charged" spring, what will the muzzle velocity be of the musket ball when it leaves the musket? Let's also assume that the spring when uncompressed, is the full length (1m) of the barrel.

PE=1/2*128*1^2=64 joules?

KE=64=1/2*.031v^2 so v=64.26m/s

64.26m/s, long way from a 1700's .69 caliber musket firing around 310m/s

Could that be right? What am I messing up?