1. The problem statement, all variables and given/known data A mass of 0.36kg hangs motionless from a vertical spring whose length is 0.8m and whose unstretched length is 0.51m. Next, the mass is pulled down to where the spring has a length of 1.09m and given an initial speed upwards of 1.2m[PLAIN]https://s3.lite.msu.edu/adm/jsMath/fonts/cmmi10/alpha/144/char3D.pngs. [Broken] What is the maximum length of the spring during the motion that follows? Maximum length= 2. Relevant equations F = k*y 1/2*k*A^2 3. The attempt at a solution k = F/y = m*g/y = 0.36kg*9.8m/s^2/(0.8m - 0.51) = 12.17793N/m Energy is conserved Let A be the maximum displacement So 1/2*k*A^2 = 1/2*k*(1.09 - 0.51)^2 + 1/2*m*v^2 so A = sqrt((1.09 - 0.51)^2 + m/k*v^2) = sqrt((1.09 -0.51)^2 + 0.36/12.18*1.2^2) = 0.5974m So the length will be 0.51 + 0.5974m = 1.11m I only have one attempt wrong, Cant find the error..