A spring with K=450N/m hangs vertically. You attach 202kg block to it and allow the mass to fall. What is the maximum distance the block will fall before it begins moving upward? ans- k=450N/m m=2.2kg x=? Fnet=mg =2.2kg*9.8N/m =21.56 N F=+/- kx x=f/k x=0.05m Is this the max distance I calcul;ated or the new equilibrium distance? Can u give me a hint.