1. The problem statement, all variables and given/known data A mass m is gently placed on the end of a freely hanging spring. The mass then falls 36 cm before it stops and begins to rise. What is the frequency of the oscillation? 2. Relevant equations f=[1/(2pi)]*[k/m]^0.5 E=KE+PE PE_s=0.5kx^2 KE=0.5mv^2 v=rw 3. The attempt at a solution So all we start off know is the amplitude is 36cm. At a peak of oscillation velocity=0 so, E=PE+KE => KE=0, E=PE E=0.5*kA^2 At equilibrium point (middle of oscillation velocity=max and PE=0) E=KE 0.5*kA^2=0.5*mv^2 v_max=wA so, 0.5*kA^2=0.5*m*w^2*A^2, A's and 0.5's cancel out (bad because only value given?) k=mw^2, w=2(pi)f k=m[2(pi)f]^2 Solve for f and I just did a proof of f=[1/(2pi)]*[k/m]^0.5 on accident and got no where...help.