A mass m is gently placed on the end of a freely hanging spring. The mass then falls 36 cm before it stops and begins to rise. What is the frequency of the oscillation?
The Attempt at a Solution
So all we start off know is the amplitude is 36cm.
At a peak of oscillation velocity=0 so,
E=PE+KE => KE=0, E=PE
At equilibrium point (middle of oscillation velocity=max and PE=0)
0.5*kA^2=0.5*m*w^2*A^2, A's and 0.5's cancel out (bad because only value given?)
Solve for f and I just did a proof of f=[1/(2pi)]*[k/m]^0.5 on accident and got no where...help.