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Spring oscillation with friction

  1. Oct 20, 2004 #1
    I think I'm getting really confused by sign changes... can someone help me with this?

    Spring with spring constat K stands vertically, and mass m is placed on top. Mass is gradually lowered to its euqilirium position. With the spring held at this compression length, the system is rotated to horizontal position. Left end of the spring is attached to a wall, and the mass is placed on a table with coefficient of kinetic friction=1/8. The mass is released.

    (a) What is the initial compression of the spring?
    (b) How much does the maximal stretch or compression of the spring decrease after each half oscillation?
    (c) How many times does the mass osciallate back and forth before coming to rest?

    (a)mgh= (1/2)kh^2
    h= 2mg/k

    (b) this is where im not sure with signs...

    conservation of energy:
    spring potential energy initial= work friction +spring potential energy
    .5k(2mg/k)^2= mg( (2mg/k) + x)/8 + .5kx^2 (?)
    i get x= (sq rt.97 -1)mg/(8k)

    that seems wrong....
     
  2. jcsd
  3. Oct 20, 2004 #2

    arildno

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    Welcome to PF!
    (a) You are asked for the EQUILIBRIUM position, not the position in which all gravitational energy has been converted into spring potential energy!!
    That is, the equilibrium position of the system is where the sum of all (vertical) forces acting on the mass is 0.
    See how this helps you along..
     
  4. Nov 1, 2004 #3
    oops.. i forgot that i posted...thanks for the help though!
     
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