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Spring potential and friction

  1. Nov 21, 2009 #1
    1. The problem statement, all variables and given/known data

    Question 6

    http://web.viu.ca/hearnd/Courses/Phys121/F02Test2/Page3.htm" [Broken]


    2. Relevant equations

    (Eps+EK)i-Ffr= (Eps+Ek)f


    3. The attempt at a solution

    both kinetics should be zero so..

    1/2(50Nm)(0.10m)2+0-(0.50kg)(9.81m/s2)uk= 1/2(50Nm)(-0.08m)2+0

    uk= (0.25-0.16)/(0.5kg)(9.81m/s2)

    this must be wrong the posted answer is different then this would yield. This seems like a very straightforward question what am I missing?

    Thanks
     
    Last edited by a moderator: May 4, 2017
  2. jcsd
  3. Nov 21, 2009 #2
    figured it out...
    Force of friction x distance in an energy equation duh.
     
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