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Introductory Physics Homework Help
Why is my method for finding the spring constant incorrect?
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[QUOTE="haruspex, post: 6835524, member: 334404"] That would be true if the stone had been released from rest at the top of the relaxed spring. But we are told it is sitting at rest on the compressed spring, which is different. Imagine it had been placed carefully on top of the uncompressed spring and released. With no losses, it would have compressed the spring by 20cm before coming instantaneously to rest, then bounced between the two extreme positions forever. Your calculation would apply to the work done against or by gravity over that full distance. In practice, there are losses and the stone eventually comes to rest with the spring compressed 10cm. Half the lost GPE has gone as heat, the other half into spring PE. [/QUOTE]
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Introductory Physics Homework Help
Why is my method for finding the spring constant incorrect?
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