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Why is my method for finding the spring constant incorrect?
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[QUOTE="josevie, post: 6835650, member: 731952"] I see now my mistake of trying to use work for a system that is on rest, thanks. That, however makes me question other things: So, if is at rest it means that -k.x = m.g, right? Does normal force has no part in it? It just came to me that I don't understand why normal force is not considered. With it being at rest and the Net Force Fn= F(spring) + F(weight), the product of it by the distance of 10cm gives me the right answer. It would, however, be a different situation of the one mentioned above? That is, it would be situation where the spring was futher compressed 10cm over the equilibrium point? I am trying to find a interpretation on why they are different (or equal). If it was released from the stop when the spring is not compressed, the work done on the spring would be the product of net force on the block over the distance of 20cm? To me the situation mentioned on the paragraph above seems exactly like this one and I am find it hard to understand the differences. They would however give me different values. I am finding it hard to understand if when working with energy, I would need to calculate it considering the distance from point where Kinect energy is highest or if I would need to calculate the work done by the block on the spring from the top to the lowest point. That has clarified some of my question, actually. Thanks! Would you mind checking some extra questions of mine that I wrote above? Wait, wouldn't the force of the stone be Fnet = F(weight) + F(spring). The force would decrease as the stone goes lower due to F(spring) increasing. They are in opposite directions. Would you mind also checking some of my doubts I wrote above? Thanks! [/QUOTE]
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Why is my method for finding the spring constant incorrect?
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