Spring powered putting machine

In summary, the student is trying to understand the homework equations and how to calculate the force required to hit a golf ball into a hole on a putting machine. They are also trying to understand what mass is and why it is needed. They are not sure if the physics behind the project is complicated or not. The student is seeking help from the community.
  • #1
dmarionk
2
0

Homework Statement



I am currently enrolled in a Engineering Drafting class. We are working on a group project where we are making a putting machine. We decided on a spring powered device. The ramp's measurements look like this where the goal is to get it into the hole at the end of the ramp.
http://i.imgur.com/o4q0D9X.jpg Its a golf ball rolling on astroturf. Heres the information he gave me when I told him I don't understand fully. http://i.imgur.com/dDhOKrO.jpg
And this is the information when he first explained it. http://i.imgur.com/A9zEuJu.jpg

From my understanding. The Professor wants the amount of force required to hit the ball into the hole. And also how much force the spring is hitting the ball with. I've only dipped my toes into the great ocean of physics and I'm still in pre-calc. This all seems very complicated to me and I have a feeling it's not that hard. Thanks in advance for your help.

Sorry for not embedding the pictures. When I did they were too big.

Homework Equations



This is for calculating the coefficient of friction.

MgH - [itex]M[/itex] /distance = 0
Mg = Mass of golfball = .099lb
H = Height = .038ft
[itex]M[/itex] = coefficient of friction
Distance = 1.65ft (average of 6 tries)
18.4375, 19, 19.3125, 20, 20.0625, 20.4375, 21.3125

The Attempt at a Solution



(.099 * .038) - ([itex]M[/itex]/1.65) = 0
.003762 - [itex]M[/itex]/1.65 = 0
-[itex]M[/itex]/1.65 = -.003762
[itex]M[/itex]/1.65 = .003762
[itex]M[/itex] = .00621
 
Last edited:
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  • #2
dmarionk said:

Homework Statement



I am currently enrolled in a Engineering Drafting class. We are working on a group project where we are making a putting machine. We decided on a spring powered device. The ramp's measurements look like this where the goal is to get it into the hole at the end of the ramp.
http://i.imgur.com/o4q0D9X.jpg Its a golf ball rolling on astroturf. Heres the information he gave me when I told him I don't understand fully. http://i.imgur.com/dDhOKrO.jpg
And this is the information when he first explained it. http://i.imgur.com/A9zEuJu.jpg

From my understanding. The Professor wants the amount of force required to hit the ball into the hole. And also how much force the spring is hitting the ball with. I've only dipped my toes into the great ocean of physics and I'm still in pre-calc. This all seems very complicated to me and I have a feeling it's not that hard. Thanks in advance for your help.

Sorry for not embedding the pictures. When I did they were too big.

Homework Equations



This is for calculating the coefficient of friction.

MgH - [itex]M[/itex] /distance = 0
Mg = Mass of golfball = .099lb
H = Height = .038ft
[itex]M[/itex] = coefficient of friction
Distance = 1.65ft (average of 6 tries)
18.4375, 19, 19.3125, 20, 20.0625, 20.4375, 21.3125

The Attempt at a Solution



(.099 * .038) - ([itex]M[/itex]/1.65) = 0
.003762 - [itex]M[/itex]/1.65 = 0
-[itex]M[/itex]/1.65 = -.003762
[itex]M[/itex]/1.65 = .003762
[itex]M[/itex] = .00621

Welcome to the PF.

So the golf ball needs to roll to the right up the ramp to get into the hole? And you need to calculate how much force to store in a spring plunger to make that happen? Then why are you calculating a mass M? Sorry that I'm not tracking what you are doing.

You should also include the energy that is invested in the rolling of the ball (that involves the moment of inertia of the ball). The energy of the ball includes the KE of the linear velocity, the PE of the height of the ball above some reference height, and the energy in the rotation of the ball. Does that help?EDIT -- Sorry, I was confused by your multiple uses of M -- why are you calculating the coefficient of friction? You want to calculate the force or impulse or energy stored in the spring pluger, right?
 
  • #3
I was following the equations that the professor wrote on the board. http://i.imgur.com/A9zEuJu.jpg shows the formula on the bottom. Friction energy was coefficient of friction from my understanding. I think I was using the wrong symbol for coefficient of friction. I thought the greek M was for coefficient of friction. The ball with be level with the astroturf pushed out of a tube by a spring. He wants some basic physics in the report. All the formulas he wrote down do not look like basic physics to me, Its something I haven't really taken yet. If you guys have any recommendations on a better example of they physics behind this project I will take all recommendations. Thank you.
 

1. What is a spring powered putting machine?

A spring powered putting machine is a device that uses a spring mechanism to launch a golf ball, allowing players to practice their putting skills without having to physically retrieve the ball after each shot.

2. How does a spring powered putting machine work?

A spring powered putting machine typically consists of a base, a spring-loaded arm, and a platform for placing the golf ball. The user pulls back the arm, stretching the spring, and then releases it to launch the ball towards the target.

3. Is a spring powered putting machine suitable for all skill levels?

Yes, a spring powered putting machine is suitable for all skill levels, from beginners to professionals. It can be adjusted to different levels of difficulty, making it a useful tool for improving putting skills at any level.

4. Can a spring powered putting machine be used indoors?

Most spring powered putting machines are designed for outdoor use, as they require a significant amount of space for the ball to travel. However, there are some models that are specifically designed for indoor use, with smaller dimensions and limited power settings.

5. How accurate is a spring powered putting machine?

The accuracy of a spring powered putting machine depends on several factors, such as the quality of the machine, the user's skill level, and the condition of the surface it is being used on. Generally, with proper setup and use, a spring powered putting machine can provide realistic and consistent results.

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