after that it is given some velocity v from down, i need to calculate how high will it go..Scott said:You don't need to compute energy here.
Just use Hooke Law directly.
What for is M applying to the spring?
How far is this causing the spring to stretch?
The assumption here is that the system is stable at x.
Is that based on some reasoning or just a wild guess?I love physics said:i used 1/2kx2=1/2mv2 is it correct?
Hooke's law is a scientific principle that describes the relationship between the force applied to an elastic object and the resulting deformation or change in length of that object. It states that the force applied is directly proportional to the extension or compression of the object, as long as the object's elastic limit is not exceeded.
The formula for Hookes law is F = -kx, where F is the force applied, k is the spring constant (a measure of the stiffness of the spring), and x is the displacement or change in length of the spring.
The unit for the spring constant in Hookes law is newtons per meter (N/m). This unit represents the amount of force required to stretch or compress the spring by one meter.
The elastic limit is the maximum amount of stress or force that can be applied to an object without causing permanent deformation or damage. In Hookes law, the elastic limit is the point at which the object stops obeying the principle and begins to behave in a non-linear manner.
Hookes law can be observed in many everyday objects, such as springs used in mattresses, car suspensions, and pogo sticks. It also applies to biological systems, such as the elasticity of blood vessels and tendons in the human body. Additionally, Hookes law is used in engineering and construction to determine the strength and stability of structures.