A spring with k = 55 N/m hangs vertically next to a ruler. The end of the spring is next to the 15 cm mark on the ruler. If a 1.9 kg mass is now attached to the end of the spring, where will the end of the spring line up with the ruler marks?(adsbygoogle = window.adsbygoogle || []).push({});

For this porblem i used the following :

W= delta Ke + delta PR

-Force of friction= 0+ ( Pe1-Pe0) + 1/2 kx^2

-Ukmgx= MG ( Y1-Y0) + 1/2 KX^2

SO WHEN I SUBSITUTE :

-Uk(1.9 KG)(9.8M/S^2)=(1.9)(9.8) +.5(55 N/M)x^2

But now i have two variables instead of one.

now when using this equation to solve im become confused because there isnt a coefficient given. I just wanted to know if i could use any other equations

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# Homework Help: Spring problem need help

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