Force of 1.5kg Crate Falling onto Spring Scale

[blackout85]

A 1.5kg crate falls from a height of 2.0m onto an industrial spring scale with a spring constant of 1.5 X 10^5 N/m. At its greatest compression the reading on the scale is:

My work:

mgh= PE
(1.5kg*9.81m/s*2.0m)= 30J
The potential energy of the crate is 30J
The Force of the crate is 1.5kg* 9.81m= 14.75
Would the force of the crate be equal to the force of compression

Thank you

 

[Locrian]

I'm not sure what you mean by "force of the crate." I also don't think using forces is a good way to solve this problem. You did a good job finding the PE at the top.

There are two ways to go from here. The better way (and also the slow way) is to turn it into two conservation of energy problems: first find the KE it attains just before hitting the spring, then find the PE of the spring after it comes to a stop.

 

[kyle8921]

for your question. Based on the information provided, it appears that the force of the crate and the force of compression would be equal. This is because the potential energy of the crate is converted into kinetic energy as it falls, and then into elastic potential energy as it compresses the spring. According to the law of conservation of energy, energy cannot be created or destroyed, only transferred from one form to another. Therefore, the force of the crate would be equal to the force of compression on the spring scale.