- #1
ace123
- 250
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If you stand on a bathroom scale, spring inside compresses .6mm, and tells your weight is 710 N. Now if you jump on the scale from a height of 1m, what does the read at it's peak?
This is what I tried to do:
I used Hooke's law: F[tex]_{}s[/tex]= k*x
and solved for the k which is spring constant.
Then I wasn't too sure of how to find the spring compression when he jumps from a height of 1m. I tried to use conservation of mechanical energy:
I did the potential energy of the the guy at 1m and set it equal to the kinetic energy when he hits the scale.
I then set up another conservation of mechanical energy for the scale. Which was Kinetic energy equal to the compression 1/2kx^2.
This is wrong however and I have no clue what else to try.
Thanks for the help
This is what I tried to do:
I used Hooke's law: F[tex]_{}s[/tex]= k*x
and solved for the k which is spring constant.
Then I wasn't too sure of how to find the spring compression when he jumps from a height of 1m. I tried to use conservation of mechanical energy:
I did the potential energy of the the guy at 1m and set it equal to the kinetic energy when he hits the scale.
I then set up another conservation of mechanical energy for the scale. Which was Kinetic energy equal to the compression 1/2kx^2.
This is wrong however and I have no clue what else to try.
Thanks for the help