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**1. Homework Statement**

A 5 kg weight hangs on a spring with spring constant k = 0.038 n/m. How far does the spring stretch?

**2. Homework Equations**

Fsp = -kX

Fnet = Fsp + Fg

**3. The Attempt at a Solution**

So I already know that Fsp = 0.038X and that Fnet = ma = 5 (-9.8)

So -49 = 0.038X + Fg.

But isn't the force of gravity equal to 5(-9.8) as well? Am I approaching the problem incorrectly?