A 1.5 kg horizontaal uniform tray is attached to a vertical ideal spring of force constant 185N/m and a 275 g metal ball is in the tray. The spring is below the tray, so it can oscillate up and down. The tray is then pushed down 15 cm below its equilibrium point called point A and released from rest. How high above point A will the tray be when the metal ball leaves the tray. Equations f=-kx E=.5 mv^2+.5 k A^2 Im thinking that this will occur when the normal force on the ball is zero. so i set up the mg=-kx and solved for x but that didnt lead me too the right answer. Any advice would be greatly appreciated.