Springs and motion of car

1. The problem statement, all variables and given/known data
A car towing a 92 kg trailor with a spring between the car and the trailor. the accelertion of the car is .3. the spring constant is 2300
how far is the spring stretched


2. Relevant equations
Fs=kx


3. The attempt at a solution

Fs=kx
ma=kx
(92)(.3)=2300x
x=.012m

i am not sure if that was legal
 

OlderDan

Science Advisor
Homework Helper
3,023
1
1. The problem statement, all variables and given/known data
A car towing a 92 kg trailor with a spring between the car and the trailor. the accelertion of the car is .3. the spring constant is 2300
how far is the spring stretched


2. Relevant equations
Fs=kx


3. The attempt at a solution

Fs=kx
ma=kx
(92)(.3)=2300x
x=.012m

i am not sure if that was legal
It is legal, but it rests on several assumptions.

1) That the units of a are m/s²

2) That the units of k are N/m

3) That the acceleration of the trailor is constant- the length of the spring is constant. In reality, it would not be if the car started moving with constant acceleration at some point in time.
 
thanks for the help
 

The Physics Forums Way

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top