Calculating Max Speed of 0.3 kg Mass on Horizontal Spring

In summary, the conversation discusses the calculation of the maximum speed a mass will attain when released from a stretched horizontal spring system. The attempted solution uses the formula Vf=squareroot of k/m(xi^2-xf^2), but is incorrect. The conversation also mentions the stretch of the spring at maximum speed and questions whether the statement is complete or if there is a frictional force involved.
  • #1
flynostrich08
20
0

Homework Statement



If a mass of 0.3 kg is attached to a horizontal spring system with a spring constant of 32 N/m^2 is stretched 0.2 m from its relaxed length, what is the maximum speed the mass will attain when released from this position?



The Attempt at a Solution


i thought all you end up with is Vf=squareroot of k/m(xi^2-xf^2) but it is wrong.
 
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  • #2
When the mass is at its maximum speed, what will be the stretch of the spring?
 
  • #3
[tex]x_i=?\mbox{ and }x_f=?{ },{ }\mbox{how do you think?}[/tex]
[tex]\mbox{does the statement is complete? frictional force?}[/tex]
 
Last edited:

What is the formula for calculating maximum speed of a 0.3 kg mass on a horizontal spring?

The formula for calculating maximum speed is v_max = √(k/m)A, where k is the spring constant, m is the mass, and A is the amplitude of the oscillation.

What is the unit for maximum speed in this calculation?

The unit for maximum speed in this calculation is meters per second (m/s).

How does the mass of the object affect the maximum speed on a horizontal spring?

The maximum speed is directly proportional to the square root of the mass of the object. This means that as the mass increases, the maximum speed will also increase.

What happens to the maximum speed if the spring constant is doubled?

If the spring constant is doubled, the maximum speed will also double. This is because the spring constant is directly proportional to the maximum speed in the formula.

Can the maximum speed ever be greater than the amplitude of the oscillation?

No, the maximum speed will always be equal to the amplitude of the oscillation. This is because the maximum speed occurs at the point where the spring is at its maximum displacement, which is also the amplitude of the oscillation.

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