Hi fellow physicists, I have some homework problems i'm trying to work through and i need to know if i'm on the right track. This is the problem: A Spring is upright (vertical) and has a constant k and a length Lo, a tray of M mass is attached to the spring and on the tray is placed a particle of m mass, suppose you initially compress the spring a distance d from the equilibrium point of the spring-tray-particle system. Calculate the maximum height above the ground the particle will reach. First i calculated the equilibrium point of the spring-tray-particle system: (Lo-L1)k = (M+m)g => L1 = Lo - (M+m)g/k Then I used the conservation of energy, Potencial energy when the spring is compressed = to kinetic energy at equilibrium point. k(d^2)/2=(M+m)(v^2)/2 => v=sqrt(k/(M+m))d Then i used the velocity to calculate the height above L1 h= k(d^2)/2g(M+m) So the height above the ground is L1 + h = Lo + (M+m)g/k +k(d^2)/2g(M+m) Is this right? i'd appreciate it if some one could double check it for me. Thanks in advance. By the way how do you use the special font for numbers and mathematical symbols?