In a military test, a 575 kg unmanned spy plane is traveling north at an altitude of 2700 m and a speed of 450 m/s. It is intercepted by a 1280 kg rocket traveling east at 725 m/s. If the rocket and spy plane become enmeshed in a tangled mess, how far from the point of impact do they hit the ground?(adsbygoogle = window.adsbygoogle || []).push({});

O.K. I take the plane is traveling northward parrallel to the ground. Conservation of momentum- and pythagorean theorum yields-

sqrt((1280 x 725)^2+(450 x 575)^2) = (1280 +575)V

Solving for V gives 519.35, and it is now a projectile motion. Solving for the time would give

-2700 = -4.905t^2

which gives time 23.46

then, I multiplied velocity x time, which gave 1.22 x 10^4, which was not the right answer. Then I saw it said distance from explosion, so it would be the hypotenuse of a 1.22 x 10^4 by 2700 triangle, giving 1.25 x 10^4.. which was still not the right answer. Anyone see where I may have gone wrong?

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# Homework Help: Spy Plane Momentum Problem

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