Square Int x: $x(x+1)(x+7)(x+8)$ is Square Integer

In summary, the given problem asks to find all integers x such that $x(x+1)(x+7)(x+8)$ is the square of an integer. Using the substitution $y = x+4$, the expression can be rewritten as $(y^2-12)^2 - y^2$. The possible solutions lie between $-9$ and $1$, as found by Albert.
  • #1
kaliprasad
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Find all integers x such that $x(x+1)(x+7)(x+8)$ is square of an integer
 
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  • #2
kaliprasad said:
Find all integers x such that $x(x+1)(x+7)(x+8)$ is square of an integer
my solution:
$x(x+1)=(x+7)(x+8)---(1)$
$x(x+7)=(x+1)(x+8)---(2)$
$x(x+8)=(x+1)(x+7)---(3)$
solution of $(1) : x=-4$
solution of $(2) : x=-4$
solution of $(3) : $ no solution
also $x(x+1)(x+7)(x+8)=0---(4)$
solution of $(4) : x=0,-1,-7,-8$
$x(x+1)(x+7)(x+8)=144---(5)$
solution of $(5):x=1,-9$
from above :$x\in$ $\left \{ 1,0,-1,-4,-7,-8,-9 \right \}$
 
Last edited:
  • #3
Albert said:
my solution:
$x(x+1)(x+7)(x+8)=144---(5)$

How ?
 
  • #4
kaliprasad said:
How ?
from (2)
$(x+1)(x+8)=x(x+7)$
$x=-4,(x+1)(x+8)=x(x+7)=-12$
$\therefore x(x+1)(x+7)(x+8)=(-12)^2=144$
 
  • #5
Albert said:
from (2)
$(x+1)(x+8)=x(x+7)$
$x=-4,(x+1)(x+8)=x(x+7)=-12$
$\therefore x(x+1)(x+7)(x+8)=(-12)^2=144$

I understand .

can u show that there is no other solution
 
  • #6
kaliprasad said:
Find all integers x such that $x(x+1)(x+7)(x+8)$ is square of an integer
[sp]Let $y = x+4$. Then $$\begin{aligned} x(x+1)(x+7)(x+8) &= (y-4)(y+4)(y-3)(y+3) \\ &= (y^2-16)(y^2-9) \\ &= y^4 - 25y^2 + 144 \\ &= (y^2-12)^2 - y^2. \end{aligned}$$ If that is a square then either $y=0$ or $y^2$ must be at least as large as the difference between $(y^2-12)^2$ and the previous square $(y^2-13)^2$. But $(y^2-12)^2 - (y^2-13)^2 = 2y^2 - 25.$ So we must have $y^2 \geqslant 2y^2 - 25$, which means that $y^2 \leqslant 25.$ Therefore $y$ lies between $-5$ and $5$, so that $x$ lies between $-9$ and $1$. The valid solutions in that interval are exactly those found by Albert.[/sp]
 
  • #7
my solution
we see that x = 0, x = -1, x = -7 and x = -8 gives the answer zero so a perfect square
let us look for other values
we have
$x(x+1)(x+7)(x+8)$
= $x(x+8)(x+1)(x+7)$
= $(x^2+8x)(x^2+8x+7)$
$= y(y+7)$ where y is $x^2+8x$
for it to be a perfect square we see that $GCD(y,y+7) = GCD(y,7)$
y cannot be a multiple of 7 because then y and y + 7 are consecutive multiples of 7 and as y is not zero product cannot
be a perfect square.
so y and y + 7 are coprimes and hence perferct squares and both are -ve of perfect squares
taking positive values let $y = n^2$ and $y+7 = m^2$
giving $n^2+7=m^2$
or $m^2-n^2 = 7$
or $(m+n)(m-n) = 7 * 1$ hence $m+n = 7, m-n= 1=>m= 4,n= 3$ giving y = 9 , y + 7 = 16
so $y = 16$
hence $x^2+8x-9=0$ giving $x = 1,=9$
taking -ve values we have $y= - 16 , y + 7 = - 9$
or $x^2+8x+ 16= 0 => x = - 4$
so we have x is one of $-9,-8,-7,-4, -1,0,1$
 

1. What does it mean for an expression to be a "Square Integer"?

A square integer is a number that can be expressed as the product of two equal integers. For example, 9 is a square integer because it can be written as 3x3. This also means that the number has an exact square root.

2. How do you know if x(x+1)(x+7)(x+8) is a square integer?

To determine if x(x+1)(x+7)(x+8) is a square integer, you would need to simplify the expression and see if it can be written as the product of two equal integers. If it can be, then it is a square integer.

3. Can x(x+1)(x+7)(x+8) be a square integer for any value of x?

No, not all values of x will result in a square integer. For example, if x=2, the expression would simplify to 168, which is not a square integer. However, there are certain values of x that will result in a square integer, such as x=0 or x=-1.

4. Is there a specific method for determining if an expression is a square integer?

Yes, there are various methods for determining if an expression is a square integer. One method is to factor the expression and see if it can be written as the product of two equal integers. Another method is to take the square root of the expression and see if it results in a whole number.

5. How is knowing if x(x+1)(x+7)(x+8) is a square integer useful in science?

Knowing if an expression is a square integer can be useful in various scientific fields, such as in number theory or in solving certain mathematical equations. It can also be helpful in understanding patterns and relationships between numbers. Additionally, the concept of square integers is often used in physics and engineering, particularly in calculations involving areas and volumes.

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