# Square Rooted varible by itself (/x) (1 Viewer)

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#### bushman91

Such a simple problem that im stuck on...

1050=2700 /d
0.388=/d

how do i get "d" by itself? ( the "/" is square root not divide)

edit: is "D" diameter or distance... one is "d" and other is "D"

Last edited:

#### newcool

#1)

$$1050=2700*/sqrt(d)$$
$$1050^2=2700^2*d$$
$$d=1050^2/2700^2 =49/324$$

#2)

$$.388=/sqrt(d)$$
$$.388^2=d$$
$$d = .15054$$

#### whozum

Square both sides

#### bushman91

thanks guys, i was thinking that, but in the question it was dealing with string vibrations were 1050hz and 2700hz and 1mm..

original question:

(1050)(/sqrt 1)=(2700)(/sqrt D)

got to that last part and forgot what to do so i did it like this:

if 1mm equals 1050hz - then 1/1050 would equal how many mm's per hz
it was 0.000952mm/1hz

so then 0.000952mm/1hz * 2700hz would equal my answer of 2.57mm but i guess its not right....

thanks again

#### hypermorphism

bushman91 said:
thanks guys, i was thinking that, but in the question it was dealing with string vibrations were 1050hz and 2700hz and 1mm..

original question:

(1050)(/sqrt 1)=(2700)(/sqrt D)
Are those slashes part of the root sign ? $1050\sqrt{1}= 2700\sqrt{D}$ ? If so, just divide both sides by 2700.

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