Square Rooted varible by itself (/x)

  • Thread starter bushman91
  • Start date
Such a simple problem that im stuck on...

1050=2700 /d
0.388=/d

how do i get "d" by itself? ( the "/" is square root not divide)



edit: is "D" diameter or distance... one is "d" and other is "D"
 
Last edited:
#1)

[tex]1050=2700*/sqrt(d)[/tex]
[tex]1050^2=2700^2*d[/tex]
[tex]d=1050^2/2700^2 =49/324[/tex]

#2)

[tex].388=/sqrt(d)[/tex]
[tex].388^2=d[/tex]
[tex]d = .15054[/tex]
 
2,208
1
Square both sides
 
thanks guys, i was thinking that, but in the question it was dealing with string vibrations were 1050hz and 2700hz and 1mm..

original question:

(1050)(/sqrt 1)=(2700)(/sqrt D)

got to that last part and forgot what to do so i did it like this:

if 1mm equals 1050hz - then 1/1050 would equal how many mm's per hz
it was 0.000952mm/1hz

so then 0.000952mm/1hz * 2700hz would equal my answer of 2.57mm but i guess its not right....

thanks again
 
bushman91 said:
thanks guys, i was thinking that, but in the question it was dealing with string vibrations were 1050hz and 2700hz and 1mm..

original question:

(1050)(/sqrt 1)=(2700)(/sqrt D)
Are those slashes part of the root sign ? [itex]1050\sqrt{1}= 2700\sqrt{D}[/itex] ? If so, just divide both sides by 2700.
 

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