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Squeeze law of limits

  1. Sep 19, 2004 #1
    i am quite confused with that law, would someone pls just explain it ina few words?
    well, the actual question goes like this:
    Use the squeez law of limits to find lim x->0 x^2cos(1/thirdrootx).

    (third root of 8 = 2 , 2x2x2 = 8, in case u do not understand what i mean by third root, i can't type the sign) :confused:
     
  2. jcsd
  3. Sep 19, 2004 #2

    Pyrrhus

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    well if you graph cos you will notice it oscillates (sp?) between -1 and 1, so if you multiply cos(angle) with x^2 it will have a "amplitud", new max values between x^2 and -x^2.

    so if you know the limit of x^2 and -x^2 you will know where does cos(angle) goes. I forgot and if the limits of both are the same!, very important.
     
  4. Sep 19, 2004 #3
    so whatever happens to the 1/thirdrootX ??
     
  5. Sep 19, 2004 #4

    Pyrrhus

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    Try many values in the calculator of any form with cosine and see what you observe.
     
  6. Sep 20, 2004 #5
    Got it!! thanks.
     
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