(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Use the Squeeze/Sandwich theorem to show the

[tex]limx->1 [(x-1)^{2}sin(\frac{1}{1-x})]=0[/tex]

Thats the lim as x approaches 1 for the whole square bracket

3. The attempt at a solution

i split it up into the two seperate limits, but i'm kinda lost on how the sandwhich theorem works, my professor said something along the lines of sin1/1-x has to be between 1 and -1 because all sin are, than he change that to an x and found the limit as x approached zero and the two limits worked out, but this limit has x approaching 1 so i'm stuck.

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# Homework Help: Squeeze/Sandwhich theorem

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