Am I able to apply the squeeze theorem to show,

-1<sin(pi/x)<1

add x^2 to the inequality

-x\<x^2sin(pi/x)\<x^2. (\< us less than or equal to)

Lim as x approaches 0 from the left side, -x^2=0; and

Lim as x approaches 0 from the right side, x^2=0

if g(x) =-x^2 F(x) = x^2sin(pi/x). h(x)= x^2

Is this the best way tom get about this question?