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Squeeze Theorem

  1. May 17, 2005 #1
    How do I solve:
    lim [(x^2-2x+1)cos(1/x^2-1)]=0
    x-1
     
  2. jcsd
  3. May 17, 2005 #2

    dextercioby

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    That limit is zero.

    [tex] \left(x^{2}-2x+1\right)(-1)\leq \left(x^{2}-2x+1\right)\left(\cos\frac{1}{x^{2}-1}\right)\leq \left(x^{2}-2x+1\right)(+1) [/tex]

    Take limit in all 3 of them and u'll have your answer.

    Daniel.
     
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