1. The problem statement, all variables and given/known data find the lim of: lim X-> -2 (3/4x) cos (4/(x+2)) 3. The attempt at a solution The x-> -2 threw me off, because the center changed. im having trouble understanding the function of the squeeze therm here. i understand that the bound is (-3/4x) and (3/4x). i also understand that the graph of the cos is shifted to the left by 2 units and so as x-> -2 it is centered at -2. i was confused when i took the lim of (-3/4x) and got (3/8), and for (3/4x) i got (-3/8). since the lim don't equal i am going assuming the lim DNE. But on the other hand when i graph (-3/4x) and (3/4x) they make and X graph centered on the origin. Also the graph of the cos(4/(2+x)) oscillates wildly at -2 but cos(4/(2+x)) is also squeezed at the origin between (-3/4x) and (3/4x). so would the lim be zero? or would it be DNE? i really think its zero since the bounds of (-3/4x) and (3/4x) squeeze cos (4/(x+2)), but i don't understand how i am supposed to do it with out a graphing calculator or graphing it by hand to see where the functions are being squeezed. Thank you in advance.