- #1
UNknown 2010
- 77
- 0
Hi
my question is
What is the molar mas of: Sr(NO3)2
1 mol Sr ((87.62 g Sr)/(1 mol Sr)) = 87.62 g
2 mol N ((14.007 g N)/(1 mol N)) = 28.014 g
6 mol O ((15.999 g O)/(1 mol o)) = 95.994 g
The molar mas is (87.62 g + 28.014 g + 95.994 g) = 211.628 g
my question is
What is the molar mas of: Sr(NO3)2
1 mol Sr ((87.62 g Sr)/(1 mol Sr)) = 87.62 g
2 mol N ((14.007 g N)/(1 mol N)) = 28.014 g
6 mol O ((15.999 g O)/(1 mol o)) = 95.994 g
The molar mas is (87.62 g + 28.014 g + 95.994 g) = 211.628 g