[tex]\int[/tex]dt' G(t-t') f(t') = 1/i [tex]\delta[/tex]/[tex]\delta[/tex]f(t)(adsbygoogle = window.adsbygoogle || []).push({});

where G(t-t') = i/ 2w exp (iw (t-t'))

I thought the RHS of the first equation is f(t). Can someone explain?

thank you

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# Homework Help: Srednicki 7.14 ND 7.16

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