Ssec^3(w)dw is very easy but you need to pay atention!

  1. Ssec^3(w)dw
    it is very easy if you use integration by parts, but you need to pay atention!

    how about use a partial fraction ? if you like to have a hard work!!

    Someone agree with me?
     
  2. jcsd
  3. HallsofIvy

    HallsofIvy 40,385
    Staff Emeritus
    Science Advisor

    Actually, the way I would do that is to write sec3w as
    1/cos3(w) and sec3(w)dw as
    cos(w)dw/cos4(w)= cos dw/(1- sin2(w))2, make the substitution u= sin(w) so the integral becomes
    ∫ du/(1-u2)2 and THEN use partial fractions. Is that what you meant?
     
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